# Finding (x,y)(x,y) of a line when given slope

**URL:** <https://forum.kirupa.com/t/finding-x-y-x-y-of-a-line-when-given-slope/242257>\
**Category:** flash\
**Created:** [October 24, 2007, 4:11am UTC](https://forum.kirupa.com/t/finding-x-y-x-y-of-a-line-when-given-slope/242257 "2007-10-24T04:11:26Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![clot](https://avatars.discourse-cdn.com/v4/letter/c/e9c0ed/32.png) [@clot](https://forum.kirupa.com/u/clot)\
**Post date:** [October 24, 2007, 4:11am UTC](https://forum.kirupa.com/t/finding-x-y-x-y-of-a-line-when-given-slope/242257/1 "2007-10-24T04:11:26Z")

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Hey all, I need is to get the x,y x,y coords (which will draw my line) from a result that describes a line with slope/intercept form. Essentially, how can I convert my result of a slope/intercept answer into something flash can understand (I assume x,y x,y). This may be easy for some of you but I appreciate the help.

The formula I (think) I have a result for is:

[FONT=Times New Roman][SIZE=3][COLOR=#000000]\*y = mx + b

What do I do with the number this gives me?

\*Any other opinions on how I should approach perpendicular bisectors would be much appreciated.

I have solved the midpoint and the slope of my original line. Essentially I want to create another line as a perpendicular bisector over my original line.  
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