# Login error

**URL:** <https://forum.kirupa.com/t/login-error/321485>\
**Category:** Uncategorized\
**Created:** [April 21, 2011, 12:45am UTC](https://forum.kirupa.com/t/login-error/321485 "2011-04-21T00:45:36Z")\
**Posts on this page:** 1\
**Page:** 1

<div class="post-metadata">

**Author:** ![iiitttaaa](https://avatars.discourse-cdn.com/v4/letter/i/a9adbd/32.png) [@iiitttaaa](https://forum.kirupa.com/u/iiitttaaa)\
**Post date:** [April 21, 2011, 12:45am UTC](https://forum.kirupa.com/t/login-error/321485/1 "2011-04-21T00:45:36Z")

</div>

i have this code

```auto
<?php
session_start();
//datos para establecer la conexion con la base de mysql.
mysql_connect('mysql1.000webhost.com','a2320543_admin','bolita1')or die ('Ha fallado la conexión: '.mysql_error());
mysql_select_db('a2320543_login')or die ('Error al seleccionar la Base de Datos: '.mysql_error());
if(isset($_POST['usuario']) && !empty($_POST['usuario']) AND isset($_POST['password']) && !empty($_POST['password'])){  
    $usuario = mysql_escape_string($_POST['name']);  
    $password = mysql_escape_string(md5($_POST['password']));  
    $active = mysql_escape_string($_POST['val']);
    $search = mysql_query("SELECT usuario, password, active FROM usuarios WHERE usuario='".$usuario."' AND password='".$password."' AND active='".$active."') or die(mysql_error());  
    $match = mysql_num_rows($search);  
 } if($match > 0){  
    echo 'Login Complete! Thanks';  
    // Set cookie / Start Session / Start Download etc...  
}else{  
    echo 'Login Failed! Please make sure that you enter the correct details and that you have activated your account.';  
    }  
?>

```

but it always thow this error:  
Parse error: syntax error, unexpected $end in /directory/validation.php on line 19

pleas help i need help