# Passing variables in a URL to use in include($variable.php); **URL:** \ **Category:** programming\ **Created:** [January 15, 2010, 3:05pm UTC](https://forum.kirupa.com/t/passing-variables-in-a-url-to-use-in-include-variable-php/303180 "2010-01-15T15:05:54Z")\ **Posts on this page:** 1\ **Page:** 1

**Author:** ![FlashFish](https://avatars.discourse-cdn.com/v4/letter/f/b9e5f3/32.png) [@FlashFish](https://forum.kirupa.com/u/FlashFish)\ **Post date:** [January 15, 2010, 3:05pm UTC](https://forum.kirupa.com/t/passing-variables-in-a-url-to-use-in-include-variable-php/303180/1 "2010-01-15T15:05:54Z")

I think the title sums it up, I’m trying to load php content into a main php page based on variables (?pag) sent from the url. These content files also use a variable (?client) to pull info from a database. Everything works on it’s own and I can include the content files with a standard: include(“overview.php”); but as soon as I start trying to swap the filename for a variable I get problems. Either I get errors or the main page loads without the content. Can somebody please check my code, this current version prodcues this error. Line 55 is the include. Parse error: syntax error, unexpected ‘.’ in /homepages/73/d165769927/htdocs/MDWEB/campaignreports/campaignreport.php on line 55 \ \ \ \ \ \ \ \ \

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'?\> \ \
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\\ \ \ \ \ \ \ Thanks in advance!