# Quick Calc I Question

**URL:** <https://forum.kirupa.com/t/quick-calc-i-question/206722>\
**Category:** random\
**Created:** [November 10, 2006, 5:44pm UTC](https://forum.kirupa.com/t/quick-calc-i-question/206722 "2006-11-10T17:44:25Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![Yeldarb](https://avatars.discourse-cdn.com/v4/letter/y/51bf81/32.png) [@Yeldarb](https://forum.kirupa.com/u/Yeldarb)\
**Post date:** [November 10, 2006, 5:44pm UTC](https://forum.kirupa.com/t/quick-calc-i-question/206722/1 "2006-11-10T17:44:25Z")

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Can someone help me out really quick? I’m pretty sure I’m accidentally doing a step twice, but I’m not sure. Could someone write out the steps to solve the definite integral of

> Integral Pi^2/16 to 0 of sin(sqrt(x)) / sqrt(x) dx

I used the Substitution method… but I’m pretty sure that I’m supposed to evaluate w/ the Second Fundamental Law of Calculus at the end and have it be -cos(Pi/4) but I get -cos(sqrt(Pi/4))

Thanks =)