# Xml flash

**URL:** <https://forum.kirupa.com/t/xml-flash/175859>\
**Category:** Uncategorized\
**Created:** [January 18, 2006, 12:16pm UTC](https://forum.kirupa.com/t/xml-flash/175859 "2006-01-18T12:16:44Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![g5604](https://avatars.discourse-cdn.com/v4/letter/g/54ee81/32.png) [@g5604](https://forum.kirupa.com/u/g5604)\
**Post date:** [January 18, 2006, 12:16pm UTC](https://forum.kirupa.com/t/xml-flash/175859/1 "2006-01-18T12:16:44Z")

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Hi,

i am trying to build a xml menu. my xml scheme looks like this:

```php
<images>    
    <pic>
        <cat></cat>
        <image></image>
        <titlename></titlename>
        <description></description>
    </pic>

</images>

```

i am trying to use cat to sort the menu into columns. for example if cat == web \_x = 300. i have not made the menu yet but i just need to know how i would go about using cat to position the menu links.

heres my code

```php
function loadXML(loaded) {
    if (loaded) {
        xmlNode = this.firstChild;
        cat = [];
        image = [];
        titlename = [];
        description = [];
        /*bodytext = [];*/
        total = xmlNode.childNodes.length;
        for (i=0; i<total; i++) {
           
            cat* = xmlNode.childNodes*.childNodes[0].firstChild.nodeValue;
            image* = xmlNode.childNodes*.childNodes[1].firstChild.nodeValue;
            titlename* = xmlNode.childNodes*.childNodes[2].firstChild.nodeValue;
            description* = xmlNode.childNodes*.childNodes[3].firstChild.nodeValue;
    
            //trace (titlename*)
            trace (cat*)
           
           
        }
        firstImage();
    } else {
        content = "file not loaded!";
    }
}

```

many thanks,  
G