A list holds n distinct numbers taken from the range 0 to n, so exactly one number in that range is missing. Write missing_number(nums) that returns it.
Examples:
missing_number([3, 0, 1])returns2missing_number([0, 1])returns2missing_number([9, 6, 4, 2, 3, 5, 7, 0, 1])returns8
def missing_number(nums):
"""The one number from 0..n that is not in nums."""
pass
Rules:
- Any language or pseudocode is fine. The stub just shows the shape.
- Say the time complexity of your approach.
- Linear time and constant extra space
Post your solution as a reply. Answer goes up in about a day.