ok,
boy math 12 feels like a long time ago now…
x^1 + x^2 + x^3 + x^4 = d
given d, how can i solve for x?
I thought I had this figured out until I realized I had calculateed for
x^1 + x^2 + x^3 + x^4 +… x^n = d
I’ll give you the solution for that anyway, maybe it will help.
The above formula can be broken down to:
x
------- = d
1 - x
which works out to become:
d
— = 1 + d
x
and then:
d
— = x
1-d
However, this only works with the equation continuing to x^n. Assuming x<1, the value of x gets smaller and smaller as it approaches the value of d. It’s essentially a probability equation.
I hope this helps you out a bit, I’ll see if I can figure out the answer to your exact question, but maybe you’ll be able to figure it out after seeing this one.
Well, Supra, there is no simple way (that I know of) to calculate the root of a polynom of the 4th degree (that’s what we call them in France…).
Degree 2: easy
Degree 3: very tricky techniques
Degree 4: I don’t think you can do that, unless it is a very simple one.
The above formula can be broken down to:
x
------- = d
1 - x
You’re sure about that? What about x=1?
pom 
whoops, edited to fix total screwup
thanks,
to the n degree is actually exactly what i’m looking for.
further research revealed the following equation:
1 - x^n
d = -----
1 - x
the equation you wrote above looks strikingly similiar.
however, isolating x is still eluding me.
This is only true if x<1. Otherwise, it will not converge to that limit. It will not converge at all, actually.
pom :asian:
OK, so you’re looking for the solution of
x^1 + x^2 + x^3 + x^4 +… x^n = d
with x < 1 and n -> infinity. Is that right?
almost.
in:
x + x^1 + x^2 … + x^n = d
given n and d, what is x?
I did verify that x<1, reread my post if you didn’t catch it the first time, ilyaslamasse (pom).
“…x<1, the value of x gets smaller and smaller…”
But anyway, the math is bogging me down. I’ll see if I can think of an answer tomorrow, with n and d defined, since my formula assumes n approaches infinity.
Oups sorry. I guess I was confused because I was thinking about a general solution to the equation. I’ll do my little research too 
pom 