ok,

boy math 12 feels like a long time ago now…

x^1 + x^2 + x^3 + x^4 = d

given d, how can i solve for x?

ok,

boy math 12 feels like a long time ago now…

x^1 + x^2 + x^3 + x^4 = d

given d, how can i solve for x?

I thought I had this figured out until I realized I had calculateed for

x^1 + x^2 + x^3 + x^4 +… x^n = d

I’ll give you the solution for that anyway, maybe it will help.

The above formula can be broken down to:

x

------- = d

1 - x

which works out to become:

d

— = 1 + d

x

and then:

d

— = x

1-d

However, this only works with the equation continuing to x^n. Assuming x<1, the value of x gets smaller and smaller as it approaches the value of d. It’s essentially a probability equation.

I hope this helps you out a bit, I’ll see if I can figure out the answer to your exact question, but maybe you’ll be able to figure it out after seeing this one.

Well, Supra, there is no simple way (that I know of) to calculate the root of a polynom of the 4th degree (that’s what we call them in France…).

Degree 2: easy

Degree 3: very tricky techniques

Degree 4: I don’t think you can do that, unless it is a very simple one.

The above formula can be broken down to:

x

------- = d

1 - x

You’re sure about that? What about x=1?

pom

*whoops, edited to fix total screwup*

thanks,

to the n degree is actually exactly what i’m looking for.

further research revealed the following equation:

```
1 - x^n
d = -----
1 - x
```

the equation you wrote above looks strikingly similiar.

however, isolating x is still eluding me.

This is only true if x<1. Otherwise, it will not converge to that limit. It will not converge at all, actually.

pom :asian:

OK, so you’re looking for the solution of

x^1 + x^2 + x^3 + x^4 +… x^n = d

with x < 1 and n -> infinity. Is that right?

almost.

in:

x + x^1 + x^2 … + x^n = d

given n and d, what is x?

I did verify that x<1, reread my post if you didn’t catch it the first time, ilyaslamasse (pom).

“…x<1, the value of x gets smaller and smaller…”

But anyway, the math is bogging me down. I’ll see if I can think of an answer tomorrow, with n and d defined, since my formula assumes n approaches infinity.

Oups sorry. I guess I was confused because I was thinking about a general solution to the equation. I’ll do my little research too

pom