This my jquery code
<script>
function sendRequest() {
//$(‘show’).innerHTML= ‘’;
$(‘loading’).innerHTML= ‘<div class=“loding”><img src=“loading.gif”></div>’;
new Ajax.Request(“product2.php”,
{
method: ‘post’,
postBody: ‘color=’+ $F(‘color’),
onComplete: showResponse
});
function showResponse(req){
$(‘show’).innerHTML= req.responseText;
$(‘show2’).innerHTML= ‘’;
$(‘loading’).innerHTML= ‘’;
}
</script>
This is my php code
<?php require_once(’…/Connections/cnn.php’); ?>
<?php
$color = $_POST[‘color’];
mysql_select_db($database_cnn, $cnn);
$query_Recordset1 = “SELECT * FROM producst WHERE 1
= '”.$color."’";
$Recordset1 = mysql_query($query_Recordset1, $cnn) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
if ($totalRows_Recordset1 > 0) {
echo ‘<table width=“100%” border=“1” cellspacing=“0” cellpadding=“0”>
<tr>’;
do {
echo '<td><img src="../photos/thumb134_'.$row_Recordset1['photo'].'" width="134" height="160"/></td>' ;
} while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));
echo ‘</tr>
</table>’ ;
}
else{
echo “result empty” ;
}
mysql_free_result($Recordset1);
?>
I want pass more variable using this method