Php parse error

1

Hi all, i tried to follow a tutorial on the website,
http://www.intranetjournal.com/articles/200408/ij_08_05_04a.html
to build a CMS website
i having a parse error on the code, but i dont see anything wrong with the coding. Hope someone here can point out my errors.

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in d:\easyphp1-8\www\cms est1.php on line 36

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in d:\easyphp1-8\www\cms est1.php on line 40

Thanks for reading.

<?php

class first_class{
var $settings;

function connection(){
    $settings['host'] = "localhost";
    $settings['username'] = "kitaeshi";
    $settings['password'] = "cheeze";
    $settings['database'] = "dababase1";
    
    return $settings;
}

}

class second_class extends first_class{

var $link;
var $theQuery;

function setConnection(){
    $setting = first_class::connection();

    $host = $settings['host'];
    $user = $settings['username'];
    $pass = $settings['password'];
    $db = $settings['database'];
    
    $this-&gt;link = mysql_connect($host, $user, $pass);
    mysql_select_db($db);
    register_shutdown_function(array(&$this, 'close'));
}

function query($query){
    $this-&gt;theQuery = $query;
    return mysql_query($query, $this-&gt;link);
}

function fetchArray($result){
    return mysql_fetch_array($result);
}

function close(){
    mysql_close($this-&gt;link);
}

}

$connector = new second_class();
$result = $connector->query(“SELECT email FROM table1”);
$row = $connector->fetchArray($result);
print $row[“email”];
?>