Search SQL with PHP in 2 fields (really help wanted)

I have a flower shop and would like to fit this function in my simple site
First i will explain how my database is made (really simple, I’m a beginner :hoser:)

Oke, here we go, i’ll do my best to explain it as good as possible

I have a database called : mysite
In this database i have a table called : products
In this table there are 4 field : id (primary key), name, productnumber & description

Example
Product a : 1, Rose, flowers54587, is red and small
Product b : 2, Sunflower, flowers54584, a sunflower is yellow and big
Product c : 3, Snowdrop, flowers54874, a snowdrop is white and tiny
Product d : 4, Daisy, flowers54583, a daisy is yellow butt small

You can visit the flowers by browsing to the page product.php?productnumber=flowers54874

I want to create like on this site a search box to look for in the database. When i enter in the box “yellow” i would like to view all the results with the link to the product page. The search machine should look in all 4 fields to find the products (about 1500 products)

Example, when you search yellow you get the product b and d.
I would like to have it like this:

You searched for “yellow”
We have 2 results:
Rose : Click to view item (product.php?productnumber=flowers54587)
Daisy : Click to view item (product.php?productnumber=flowers54583)

This is what i have now:

Page 1 : index.php
<form method=“post” action=“search.php”>
<input type=“row_name1” name=“search” size=“25”>
<input type=“submit” value=“Begin Searching!!”>
</form>

Page 2 : search.php
<?
$hostname = “localhost”;
$dbName = “mysite”;
$username = “xxxxxxx”;
$password = " xxxxxxx ";
$usertable = “products”;

MYSQL_CONNECT($hostname, $username, $password) OR DIE(“Unable to connect to database”);
@mysql_select_db( “$dbName”) or die( “Unable to select database”);
?>
<?
//error message (not found message)
$XX = “No Record Found”;
$query = mysql_query(“SELECT * FROM $usertable WHERE $_POST[metode] LIKE ‘%$search%’ LIMIT 0, 30 “);
while ($row = mysql_fetch_array($query))
{
$variable1=$row[“name”];
print (“this is for $variable1”);
}
//below this is the function for no record!!
if (!$variable1)
{
print (”$XX”);
}
//end
?>

It would be great if you could help me to fix the probably stupid mistake
Really thanks and hope to hear soon from you, i can’t wait to view what i did wrong.

=) Greeting from Steven (Belgium, Europe)