Spot the bug - #59

There is one subtle logic bug.

function hasDuplicate(nums) {
  const seen = new Set();
  for (const n of nums) {
    if (seen.has(n)) {
      return false;
    }
    seen.add(n);
  }
  return true;
}

console.log(hasDuplicate([2, 7, 4, 7]));

Reply with what is broken and how you would fix it.

1 Like

Your return values are backwards. Hitting seen.has(n) means you found a duplicate, so hasDuplicate should return true there, and only return false after the loop finishes with no repeats.

I’d flip the returns:

function hasDuplicate(nums) {
  const seen = new Set();
  for (const n of nums) {
    if (seen.has(n)) return true;
    seen.add(n);
  }
  return false;
}

console.log(hasDuplicate([2, 7, 4, 7])); // true
1 Like