Trigonometry: finding the angle

1

basically i have two movie clips. i know the x diff and the y diff, now how do i find the angle at which the movie clips are at?


                    v MC 2
                   /|
                  / |
                 /  | < y diff
                /   |
MC 1  >         /__|
             ^   \
      angle      x diff

i hope that’s clear enough

-mike

2

ooops, the diagram got screwed up when i posted…

3

eh, i sort of fixed it for you…

4

thanks jubba :slight_smile:

5

rad_deg = Math.PI / 180;
angle = Math.atan2 (y_diff, x_diff);
angle /= rad_deg; //to convert to degrees

note: hope u know about CAST rule, cuz u need

maybe try reading about Math.atan also…

6

i tried that and it didn’t work. i probably didn’t do it right. here’s my script:

[AS]diffx = MC1._x - MC2._x
diffy = MC1._y - MC2._y
ang = Math.atan2(diffx, diffy);
this.dx = Math.cos(this.ang)*this.speed;
this.dy = Math.sin(this.ang)this.speed;
this._x += this.dx;
this._y += this.dy;
this._rotation = this.ang(180/Math.PI);[/AS]

i want MC1 to move towards MC2. maybe my approach is totaly wrong…:-\

7

oh, yeah, the above script is in an onEnterFrame function and all that it does is make MC1 move to the right horizontaly

8

ummm, do u know about the CAST rule?

9

nope, is it important? if it is can you please give a brief explanation? thatnks

10

S | A
|_
T | C

C: cosine
A: all
S: sine
T: tangent
these are the quadrant that are positive

11

ahh… nevermind, simple scripting error, your way works. thanks a lot :slight_smile: