Hi There,
I’m working on a project in which sound plays an important part.
I want to be able to adjust the volume of two sounds independently, ánd have access to the position in the soundfile.
The code below plays 2 soundfiles (“L36 Bass.wav” & “L36 Perc.wav”). The sounds are declared as ‘new Sound’ with qualifiers
(“L36Bass” and “L36Perc” recpectively) in line 03 & 04 within empty movieclips, to allow individual volume-adjustments.
The volume-mix between the 2 is then governed by the x-mouse position (line 10 - 16):
01 this.createEmptyMovieClip(“L36Bass”, 1)
02 this.createEmptyMovieClip(“L36Perc”, 2)
03 SndBass = new Sound(“L36Bass”)
04 SndPerc = new Sound(“L36Perc”);
05 SndBass.attachSound(“L36 Bass.wav”);
06 SndPerc.attachSound(“L36 Perc.wav”);
07 SndBass.start()
08 SndPerc.start();
09 this.onEnterFrame = function ()
10 { onMouseMove = function ()
11 { xf = _root._xmouse / Stage.width;
12 if ( xf > 0.5 )
13 { volBass = 100; volPerc = 200 * ( 1 - xf ) }
14 else
15 { volPerc = 100; volBass = 200 * xf }
16 SndBass.setVolume(vBass); SndPerc.setVolume(vPerc);
17 }
18 SndBass.onSoundComplete = function()
19 { SndBass.start(); SndPerc.start(); }
20 }
This works just fine (as long as the WAV-files are in the library and the option ‘Export for Actionscript’ is selected).
However, when I try to access the position within a soundfile with the statement
SndBass.position;
this results in an ‘undefined-error’.
When I remove the qualifier in line 03, and go for ‘SndBass = new Sound()’ in stead of ‘SndBass = new Sound(“L36Bass”)’, the property SndBass.position is available, but, as expected, the individual volume-control is lost.
Any suggestons?
