it’s a tricky one
a boat travels downstream 300 miles in the same time that it travels upstream 200 miles…if current is constant, wut is the speed of the boat in still water
250 miles / time?
(/ being divided by)
I am getting what harish posted. Is there one correct solution for this? There can be a near infinite set of solutions, because there are two unknowns (the boat’s speed, and the current’s speed). Manipulating both of those unknowns can give you any host of solutions for traveling 300m downstream and 200m upstream in the same time.
Case 1: Downstream
300m = (boat_speed + current_speed)*t
Case 2: Upstream
200m = (boat_speed - current_speed)*t
Combining both equations, the current’s speed is removed, and you are left with 250m = t*boat_speed.
:hr:
Yep. As I explained to him on IM.
I don’t understand what he finds challenging about it 
x+y=300
x-y=200
x=200+y
200+2y=300
2y=100
y=50 (current)
200+50=250
300-50=250
or you could get the mean of the two numbers.
