Ok, my grandad gave me this brainteaser and I thought it was cool - see if you can get it.
You have 12 identical coins, but one is a different weight to the others. (maybe heavier, maybe lighter, you don’t know which) You also have a pair of scales (the balance type where you load stuff on each end and see if it balances) You are only allowed 3 ‘weighings’ to find out which coin is the odd one and whether it is heavier or lighter.
Me and my dad came up with an answer, but it seems really complex.
Divide the pile into goups of 4, so 3 groups, weigh 2 of them. If they weigh the same its the 3rd pile, otherwise its the different scale (heavier one I am going to have to go with) then you divide that pile in half. weigh em both, then divide agian, weigh again.
That only works if you know it is heavier or lighter though, thats a cool puzzle!
Yeah - one ‘set’ of scales, sorry if that’s confusing. But you don’t need two scales anyway for your answer? But that would be an interesting problem in itself… :ponder:
My answer is still within 3 weighs, works when nit’s heavier or lighter, it’s legit, but it just seems really messy and hard to explain/do, whereas most of these things have a simpler “Why didn’t I think of that!” sort of answer, if you see what I mean
We wrote out our answer to explain to my grandad - I’ll post it up when I can get it off my dad’s laptop. I’d be interested to see what you’ve got.
Yeah i worked it out for 3 weighings, pretty simple. Howd u get 2 weighings hybrid?? That dont seem possible. Ill have a bit more a of a think about it.
you have to be able to work out which is lighter/heavier as well… its no use saying you can work it out if you ignore that part, because thats the whole point of the puzzle, to work it out WITH those parameters.
wow that sure is long and complex…
seems to work, but it’s one of those things where if you DID make a logic mistake, it’d be hard to pick up.
so i ended up just doing a google search and found a site with teh answer, it’s the same kind of procedure as you did, but they numbered the coins and it made it a lot clearer. I think theirs actually WAS shorter too.
nah, because they could argue that the difference in weight is so small that you wouldn’t hear a difference, nor could you tell if it was heavier or lighter.
my original solution was similar - just use your hands to weigh each coin and find the one that is different but it’s not really valid i think.